The solution of exercise 3.6 of class 10th of question no.1 How i solve this question in simple way. Because it is very important for class 10 Solve the following pairs of equations by reducing them to a pair of linear equations: (v) (7x-2y)/ xy = 5 (8x + 7y)/xy = 15

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# Solve the following pairs of equations by reducing them to a pair of linear equations: (v) (7x-2y)/ xy = 5 (8x + 7y)/xy = 15 Q.1(5)

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(7x-2y)/ xy = 5

7/y – 2/x = 5…………………………..(i)

(8x + 7y)/xy = 15

8/y + 7/x = 15…………………………(ii)

Substituting 1/x =m in the given equation we get,

– 2m + 7n = 5 => -2 + 7n – 5 = 0 ……..(iii)

7m + 8n = 15 => 7m + 8n – 15 = 0 ……(iv)

By cross-multiplication method, we get,

m/(-105-(-40)) = n/(-35-30) = 1/(-16-49)

m/(-65) = n/(-65) = 1/(-65)

m/-65 = 1/-65

m = 1

n/(-65) = 1/(-65)

n = 1

m = 1 and n = 1

m = 1/x = 1 n = 1/x = 1

Therefore, x = 1 and y = 1