The best way of simply the question of exercise 3.6 of 10th class math. This is an important question. How i solve easily Solve the following pairs of equations by reducing them to a pair of linear equations: (iii) 4/x + 3y = 14 3/x -4y = 23

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# Solve the following pairs of equations by reducing them to a pair of linear equations: (iii) 4/x + 3y = 14 3/x -4y = 23 Q.1(3)

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Putting in the given equation we get,

So, 4m + 3y = 14 => 4m + 3y – 14 = 0 ……………..…..(1)

3m – 4y = 23 => 3m – 4y – 23 = 0 ……………………….(2)

By cross-multiplication, we get,

m/(-69-56) = y/(-42-(-92)) = 1/(-16-9)

-m/125 = y/50 = -1/ 25

-m/125 = -1/25 and y/50 = -1/25

m = 5 and b = -2

m = 1/x = 5

So , x = 1/5

y = -2