One of the most important and conceptual question from linear equations in two variables in which we have given two equations 4x-3y=8, 6x-y=29/3 and we have been asked to find x and y in the above equations
Kindly solve these equations
RS Aggarwal, Class 10, chapter 3B, question no 9
The given system of equation is:
4x – 3y = 8 ……(i)
6x – y = 29/ 3 ……(ii)
On multiplying (ii) by 3, we get: 18x – 3y = 29 ….(iii)
On subtracting (iii) from (i) we get: -14x = -21
x = 21/14
= 3/2
Now, substituting the value of x = 3/2 in (i), we get:
4 × 3/2 – 3y = 8
⇒6 – 3y = 8
⇒3y = 6 – 8 = -2
y = −2/ 3
Hence, the solution x = 3/2 and y = −2/3