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Show that: (ii) cos 38° cos 52° – sin 38° sin 52° = 0. Q.2(2)

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Find the solution of  the ncert class 10 of introduction of  trigonometry  of exercise 8.2  please help me to solve the question number 2(2) easily and quickly and give me the best solution of the introduction of  trigonometry .Show that: (ii) cos 38° cos 52° – sin 38° sin 52° = 0.

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  1. cos 38° cos 52° – sin 38° sin 52°

    Simplify the given problem by converting some of the cos functions to the sin functions

    We know that,

    cos 38° = cos (90° – 52°) = sin 52°

    cos 52°= cos (90°-38°) = sin 38°

    = cos (90° – 52°) cos (90°-38°) – sin 38° sin 52°

    Substitute the values

    = sin 52° sin 38° – sin 38° sin 52° = 0

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