Find the easiest solution of the chapter number systems of class 9th ncert ,how i solve the tough question of exercise 1.5 question number 5 (1),(2) . Find the best solution of this question also find the simplest method of this question. Rationalize the denominators of the following: (i) 1/√7, (ii) 1/(√7-√6)
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Rationalize the denominators of the following: (i) 1/√7, (ii) 1/(√7-√6) . Q.5(i),(ii)
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(i) 1/√7
Solution:
Multiply and divide 1/√7 by √7
(1×√7)/(√7×√7) = √7/7
(ii) 1/(√7-√6)
Solution:
Multiply and divide 1/(√7-√6) by (√7+√6)
[1/(√7-√6)]×(√7+√6)/(√7+√6) = (√7+√6)/(√7-√6)(√7+√6)
= (√7+√6)/√72-√62 [denominator is obtained by the property, (a+b)(a-b) = a2-b2]
= (√7+√6)/(7-6)
= (√7+√6)/1
= √7+√6