Adv
Sonu
  • 0
Newbie

Rationalize the denominators of the following: (i) 1/√7, (ii) 1/(√7-√6) . Q.5(i),(ii)

  • 0

Find the easiest solution of the chapter number systems of class 9th ncert ,how i solve the tough question of exercise 1.5 question number 5 (1),(2) . Find the best solution of this question  also find the simplest method of this question. Rationalize the denominators of the following: (i) 1/√7, (ii) 1/(√7-√6)

Share

1 Answer

  1. (i) 1/√7

    Solution:

    Multiply and divide 1/√7 by √7

    (1×√7)/(√7×√7) = √7/7

    (ii) 1/(√7-√6)

    Solution:

    Multiply and divide 1/(√7-√6) by (√7+√6)

    [1/(√7-√6)]×(√7+√6)/(√7+√6) = (√7+√6)/(√7-√6)(√7+√6)

     

    = (√7+√6)/√72-√6[denominator is obtained by the property, (a+b)(a-b) = a2-b2]

    = (√7+√6)/(7-6)

    = (√7+√6)/1

    = √7+√6

    • 0
Leave an answer

Leave an answer

Browse

Choose from here the video type.

Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs".

Captcha Click on image to update the captcha.

Related Questions