Find the easiest solution of the chapter number systems of class 9th ncert ,how i solve the tough question of exercise 1.5 question number 5 (1),(2) . Find the best solution of this question also find the simplest method of this question. Rationalize the denominators of the following: (i) 1/√7, (ii) 1/(√7-√6)

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# Rationalize the denominators of the following: (i) 1/√7, (ii) 1/(√7-√6) . Q.5(i),(ii)

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(i) 1/√7Solution:

Multiply and divide 1/√7 by √7

(1×√7)/(√7×√7) = √7/7

(ii) 1/(√7-√6)Solution:

Multiply and divide 1/(√7-√6) by (√7+√6)

[1/(√7-√6)]×(√7+√6)/(√7+√6) = (√7+√6)/(√7-√6)(√7+√6)

= (√7+√6)/√7

^{2}-√6^{2 }[denominator is obtained by the property, (a+b)(a-b) = a^{2}-b^{2}]= (√7+√6)/(7-6)

= (√7+√6)/1

= √7+√6