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Question 13. Find the sum:(i) 2 + 4 + 6 + . . . + 200

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This is an arithmetic progression based question from Chapter name- Arithmetic Progression
Chapter number- 9
Exercise – 9.6
In this question we have been given the arithmetic progression. Also we have to find the sum of it.

CBSE DHANPAT RAI PUBLICATIONS
Understanding CBSE Mathematics
Class :- 10th
Question no 13(i)

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1 Answer

  1. Given series is an A.P. with first term(a) = 2,

    Common difference(d) = 4 − 2 = 2 and nth term(an) = 200.

    We know nth term of an A.P. is given by, an = a + (n − 1)d.

    => 200 = 2 + (n − 1)2

    => 200 = 2 + 2n − 2

    => n = 200/2

    => n = 100

    Also we know sum of n terms of an A.P. is given by Sn = n[a + an]/2.

    S100 = 100[2 + 200]/2

    = 100[101] = 10100

    Hence, the sum of terms of the given series is 10100.

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