This is an arithmetic progression based question from Chapter name- Arithmetic Progression
Chapter number- 9
Exercise – 9.6
In this question we have been given the arithmetic progression. Also we have to find the sum of it.
CBSE DHANPAT RAI PUBLICATIONS
Understanding CBSE Mathematics
Class :- 10th
Question no 13(i)
Given series is an A.P. with first term(a) = 2,
Common difference(d) = 4 − 2 = 2 and nth term(an) = 200.
We know nth term of an A.P. is given by, an = a + (n − 1)d.
=> 200 = 2 + (n − 1)2
=> 200 = 2 + 2n − 2
=> n = 200/2
=> n = 100
Also we know sum of n terms of an A.P. is given by Sn = n[a + an]/2.
S100 = 100[2 + 200]/2
= 100[101] = 10100
Hence, the sum of terms of the given series is 10100.