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Question 1. Find the sum of the following arithmetic progressions(viii) –26, –24, –22,…. to 36 terms

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This is the basic and conceptual question from Chapter name- Arithmetic Progression
Chapter number- 9
Exercise 9.6

In this question we have been given an arithmetic progression. And we have to find its sum upto 36 terms.

CBSE DHANPAT RAI publications
Class:- 10th
Solutions of CBSE Mathematics
Question 1(viii)

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1 Answer

  1. Given A.P. has first term(a) = -26,

     

     

    Common difference(d) = -24 – (-26) = 2

    and number of terms(n) = n.

    So, Sum of A.P. = S36 = n[2a + (n – 1)d] / 2

    = 36[2(-26) + (36 – 1)2]/2

    = 18[-52 + 70] = 324

    Hence, the sum of the first 36 terms of A.P. is 324.

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