0 Deepak Bora Asked: July 10, 20202020-07-10T20:16:13+05:30 2020-07-10T20:16:13+05:30In: CBSE Quadratic equations, find the value of k for which the roots are real and equal 0 Find the value of k for which the equation x^{2} + k(2x + k – 1) + 2 = 0 has real and equal roots chapter 4class10thdiscriminantnature of rootsquadratic equations Share Facebook Related Questions Without using trigonometric tables, evaluate the following (i) (sin 65o/ cos 25o) + (cos 32o/sin 58o) – sin ... Find the value of m so that the quadratic equation mx (x – 7) + 49 = 0 ... If the quadratic equation px² -2√5 px + 15 = 0 has two equal roots, then find the ... Find a quadratic polynomial, the sum and product of whose zeroes are √3 and 1/√3 respectively. Form a quadratic polynomial whose zeroes are 3 + √2 and 3 – √2. 1 Answer Voted Oldest Recent Deepak Bora 2020-07-13T17:37:25+05:30Added an answer on July 13, 2020 at 5:37 pm x²+ k(2x+k-1)+2=0 x²+2kx+k²-k+2=0 After comparing ax²+bx+c=0 a=1, b= 2k & c= k²-k+2 Because our roots are real and equal ∴ D= 0 b²-4ac= 0 (2k)²-4(1)(k²-k+2)=0 4k²-4k²+4k-8=0 4k=8 ∴ K= 2 0 Reply Share Share Share on Facebook Share on Twitter Share on LinkedIn Share on WhatsApp Leave an answerLeave an answerCancel reply Featured image Select file Browse Add a Video to describe the problem better. Video type Youtube Vimeo Dailymotion Facebook Choose from here the video type. Video ID Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs". Click on image to update the captcha. Save my name, email, and website in this browser for the next time I comment.

x²+ k(2x+k-1)+2=0

x²+2kx+k²-k+2=0

After comparing ax²+bx+c=0

a=1, b= 2k & c= k²-k+2

Because our roots are real and equal

∴ D= 0

b²-4ac= 0

(2k)²-4(1)(k²-k+2)=0

4k²-4k²+4k-8=0

4k=8

∴ K= 2