Quadratic equation class 10, find the value of discriminant, and the value of D is 0 if roots are equal. this is very important question for the board examinations,
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Quadratic equations class 10, to find the value of p for this equation px² –2√5 px + 15 = 0 you have to put the value of (D) b²-4ac = 0, because the roots are given equal.
this is a real-life situation where you need to find the nature of roots to confirm whether this situation is possible or not, ncert maths solutions class 10
ncert maths solution class 10 chapter 4, quadratic equations
solve question number 2 (i),exercise 4.4,chapter 4, quadratic equations, NCERT
Find the values of p for which the quadratic equation 4x2 + px + 3 = 0 has equal roots.
Find the value of k for which the equation x2 + k(2x + k – 1) + 2 = 0 has real and equal roots
The quadratic equation px² – 2 px + 15 = 0 has two equal roots, then find the value of p.