This question is from trigonometry topic – trigonometric identities in which we have to prove that (1+cosθ+sinθ)/(1+cosθ-sinθ) = (1+sinθ)/cosθ
RS Aggarwal, Class 10, chapter 13A, question no 27(i).
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LHS = (1+cosθ+sinθ)/(1+cosθ-sinθ)
=(1+cosθ+sinθ)(1+cosθ+sinθ)/(1+cosθ-sinθ)(1+cosθ+sinθ)
=(1+cosθ+sinθ+cosθsinθ)/(1+cosθ)cosθ
=(1+sinθ)/cosθ
=RHS