Find the best way to solve the ncert class 10 questions of coordinate geometry in the simplest form .How i solve this problem quickly and best solutions of the exercise 7.4 question no. 7(2) . Let A (4, 2), B (6, 5) and C (1, 4) be the vertices of ∆ ABC.(ii) Find the coordinates of the point P on AD such that AP : PD = 2 : 1.
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Let A (4, 2), B (6, 5) and C (1, 4) be the vertices of ∆ ABC.(ii) Find the coordinates of the point P on AD such that AP : PD = 2 : 1. Q.7(2)
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(ii) Coordinates of P can be calculated as follows:
Coordinates of P = ( [2(7/2) + 1(4)]/(2 + 1), [2(9/2) + 1(2)]/(2 + 1) ) = (11/3, 11/3)
So, P is (11/3, 11/3)