Adv
deepaksoni
  • 1
Guru

In the figure, not drawn to scale, TF is a tower. The elevation of T from A is x0 where tan x = 2/5 and AF = 200 m. The elevation of T from B, where AB = 80 m, is y0. Calculate: (i) the height of the tower TF. (ii) the angle y, correct to the nearest degree.

  • 1

sir this is the important  question from the book -ML aggarwal( avichal publication) class 10th , chapter20 , heights and distances
it is given that In the figure, not drawn to scale, TF is a tower.
The elevation of T from A is x0 where tan x = 2/5 and AF = 200 m.
The elevation of T from B, where AB = 80 m, is y0.
Calculate: (i) the height of the tower TF.
(ii) the angle y, correct to the nearest degree.

question no 22 , heights and distances , ICSE board

 

Share

1 Answer

  1. Consider the height of the tower TF = x

    It is given that

    tan x = 2/5, AF = 200 m, AB = 80 m

    (i) In right triangle ATF

    tan x0 = TF/AF

    Substituting the values

    2/5 = x/200

    So we get

    x = (2 × 200)/ 5

    x = 400/5

    x = 80 m

    Hence, the height of tower is 80 m.

    (ii) In right triangle TBF

    tan y = TF/BF

    Substituting the values

    tan y = 80/ (200 – 80)

    tan y = 80/120

    tan y = 2/3 = 0.6667

    So we get

    y = 330 41’ = 340

    • 1
Leave an answer

Leave an answer

Browse

Choose from here the video type.

Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs".

Captcha Click on image to update the captcha.

Related Questions