What is the best way to solve the problem of triangles of exercise 6.3 of math, how i solve easily this question easily In the figure, ABC and AMP are two right triangles, right angled at B and M respectively, prove that:

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# In the figure, ABC and AMP are two right triangles, right angled at B and M respectively, prove that: Q.9

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(i) ΔABC ~ ΔAMP(ii) CA/PA = BC/MPGiven, ABC and AMP are two right triangles, right angled at B and M respectively.

(i) In ΔABC and ΔAMP, we have,

∠CAB = ∠MAP (common angles)

∠ABC = ∠AMP = 90° (each 90°)

∴ ΔABC ~ ΔAMP (AA similarity criterion)

(ii) As, ΔABC ~ ΔAMP (AA similarity criterion)

If two triangles are similar then the corresponding sides are always equal,

Hence, CA/PA = BC/MP