What is the best way to solve the problem of triangles of exercise 6.3 of math, how i solve easily this question easily In the figure, ABC and AMP are two right triangles, right angled at B and M respectively, prove that:
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In the figure, ABC and AMP are two right triangles, right angled at B and M respectively, prove that: Q.9
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(i) ΔABC ~ ΔAMP
(ii) CA/PA = BC/MP
Given, ABC and AMP are two right triangles, right angled at B and M respectively.
(i) In ΔABC and ΔAMP, we have,
∠CAB = ∠MAP (common angles)
∠ABC = ∠AMP = 90° (each 90°)
∴ ΔABC ~ ΔAMP (AA similarity criterion)
(ii) As, ΔABC ~ ΔAMP (AA similarity criterion)
If two triangles are similar then the corresponding sides are always equal,
Hence, CA/PA = BC/MP