(i) In this question we have been asked to prove that from the given figure two triangles are similar

(ii) In the given question we are asked to calculate the length of sides of triangle

ML Aggarwal Avichal Publication, Similarity, question no 8(b)

## (i) We have to prove that, △ACO∼△BDO.

So, from the figure

Consider △ACO and △BDO

Then,

∠AOC=∠BOD [from vertically opposite angles]

∠A=∠B

Therefore, △ACO=△BDO

Given, BD=2.4 cm,OD=4 cm,OB=3.2 cm,AC=3.6 cm,

△ACO∼△BOD

So, AO/OB=CO/OD=AC/BD

Consider AC/BD=AO/OB

3.6/2.4=AO/3.2

O=(3.6×3.2)/2.4

AO=4.8cm

Now, consider AC/BD=CO/OD

3.6/2.4=CO/4

CO=(3.6×4)/2.4

CO=6cm.