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Rajan@2021
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In the figure (2) given below, CA∥BD, the lines AB and CD meet at G. (i) Prove that △ACO∼△BDO. (ii) If BD=2.4 cm,OD=4 cm,OB=3.2 cm and AC=3.6 cm, calculate OA and OC.

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(i)  In this question we have been asked to prove that from the given figure two triangles are similar

(ii) In the given question we are asked to calculate the length of sides of triangle

ML Aggarwal Avichal Publication, Similarity, question no 8(b)

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1 Answer

  1. (i) We have to prove that, ACOBDO.
    So, from the figure
    Consider ACO and BDO
    Then,
    AOC=BOD [from vertically opposite angles]
    A=B
    Therefore, ACO=BDO
    Given, BD=2.4 cm,OD=4 cm,OB=3.2 cm,AC=3.6 cm,
    ACOBOD
    So, AO/OB=CO/OD=AC/BD
    Consider AC/BD=AO/OB
    3.6/2.4=AO/3.2
    O=(3.6×3.2)/2.4
    AO=4.8cm
    Now, consider AC/BD=CO/OD
    3.6/2.4=CO/4
    CO=(3.6×4)/2.4
    CO=6cm.

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