Adv
AnilSinghBora
  • 0
Guru

In Fig. 6.31, if PQ ST, PQR = 110° and RST = 130°, find QRS. [Hint : Draw a line parallel to ST through point R.] Q.4

  • 0

Please give me the best way for solving the problem of class 9th ncert math of Lines and Angles chapter of math of class 9th of exercise 6.2of question no 4 what is the tricky way for solving this question In Fig. 6.31, if PQ ST, PQR = 110° and RST = 130°, find QRS. [Hint : Draw a line parallel to ST through point R.]

Share

1 Answer

  1. First, construct a line XY parallel to PQ.

    Ncert solutions class 9 chapter 6-11

    We know that the angles on the same side of transversal is equal to 180°.

    So, PQR+QRX = 180°

    Or,QRX = 180°-110°

    ∴ QRX = 70°

    Similarly,

    RST +SRY = 180°

    Or, SRY = 180°- 130°

    ∴ SRY = 50°

    Now, for the linear pairs on the line XY-

    QRX+QRS+SRY = 180°

    Putting their respective values, we get,

    QRS = 180° – 70° – 50°

    Hence, QRS = 60°

    • 0
Leave an answer

Leave an answer

Browse

Choose from here the video type.

Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs".

Captcha Click on image to update the captcha.

Related Questions