What is the best way for solving the question from class 9th ncert math of Circles chapter of Ncert of exercise 10.5of math. What is the best way for solving this question please guide me the best way for solving this question no 1 In Fig. 10.36, A,B and C are three points on a circle with centre O such that BOC = 30° and AOB = 60°. If D is a point on the circle other than the arc ABC, find ADC.
It is given that,
AOC = AOB+BOC
So, AOC = 60°+30°
∴ AOC = 90°
It is known that an angle which is subtended by an arc at the centre of the circle is double the angle subtended by that arc at any point on the remaining part of the circle.
So,
ADC = (½)AOC
= (½)× 90° = 45°