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## Prove that a cyclic parallelogram is a rectangle. Q.12

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How can i solve this tough question of class 9th ncert of Circles of math of exercise 10.5 of question ...Read more

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## ABC and ADC are two right triangles with common hypotenuse AC. Prove that ∠ CAD = ∠CBD. Q.11

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Give me the best way for solving the question of class 9th of Circles of exercise 10.5 of math. Give ...Read more

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## If circles are drawn taking two sides of a triangle as diameters, prove that the point of intersection of these circles lie on the third side. Q.10

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How i find the best tricky way for solving the question of class 9th of Circles chapter of class 9th ...Read more

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## Two circles intersect at two points B and C. Through B, two line segments ABD and PBQ are drawn to intersect the circles at A, D and P, Q respectively (see Fig. 10.40). Prove that ∠ ACP = ∠ QCD. Q.9

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What is the easiest way for solving the question of class 9th ncert math of exercise 10.5of math of Circles ...Read more

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## If the non-parallel sides of a trapezium are equal, prove that it is cyclic. Q.8

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what is the tricky way for solving the question of class 9th ncert math of Circles chapter of ncert of ...Read more

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## If diagonals of a cyclic quadrilateral are diameters of the circle through the vertices of the quadrilateral, prove that it is a rectangle. Q.7

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Yesterday i was doing the question from class 9th ncert book of math of Circles chapter of exercise 10.5  What ...Read more

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## ABCD is a cyclic quadrilateral whose diagonals intersect at a point E. If ∠ DBC = 70°, ∠ BAC is 30°, find ∠ BCD. Further, if AB = BC, find ∠ ECD. Q.6

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Please give me the best way for solving the problem of class 9th ncert math of Circles chapter of math ...Read more

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## In Fig. 10.39, A, B, C and D are four points on a circle. AC and BD intersect at a point E such that ∠ BEC = 130° and ∠ ECD = 20°. Find BAC. Ncert solutions class 9 chapter 10-20 Q.5

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Please guide me the best way for solving the question of class 9th math of Circles chapter of exercise 10.5of ...Read more

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## In Fig. 10.38, ABC = 69°, ACB = 31°, find BDC. Q.4

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How i solve the question of class 9th ncert math of Circles chapter of exercise 10.5of question no 4. I ...Read more

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## In Fig. 10.37, PQR = 100°, where P, Q and R are points on a circle with centre O. Find OPR. Q.3

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Hello sir i want to know the best solution of the question from exercise 10.5of math of Circles chapter of ...Read more