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In an AP(vii) Given a = 8, an = 62, Sn = 210, find n and d. Q.3(7)

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In exercise 5.3 of arithmetic progressions of math of class 10th. How i solve this tough question in easy way In an AP(vii) Given a = 8, an = 62, Sn = 210, find n and d.

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  1. Given that, a = 8, an = 62, Sn = 210

    As, sum of n terms in an AP is,

    Sn = n/2 (a + an)

    210 = n/2 (8 +62)

    ⇒ 35n = 210

    ⇒ n = 210/35 = 6

    Now, 62 = 8+5d

    ⇒ 5d = 62-8 = 54

    ⇒ d = 54/5 = 10.8

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