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AnilSinghBora
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In an AP(ix) Given a = 3, n = 8, S = 192, find d.. Q.3(9)

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Give me solution of class 10 exercise 5.3 Ques. no.3 . Easy and best way to solve this questions solution. In an AP(ix) Given a = 3, n = 8, S = 192, find d

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  1. Given that, first term, a = 3,

    Number of terms, n = 8

    And sum of n terms, S = 192

    As we know,

    Sn = n/2 [2a+(n -1)d]

    192 = 8/2 [2×3+(8 -1)d]

    192 = 4[6 +7d]

    48 = 6+7d

    42 = 7d

    d = 6

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