Give me solution of class 10 exercise 5.3 Ques. no.3 . Easy and best way to solve this questions solution. In an AP(ix) Given a = 3, n = 8, S = 192, find d
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Given that, first term, a = 3,
Number of terms, n = 8
And sum of n terms, S = 192
As we know,
Sn = n/2 [2a+(n -1)d]
192 = 8/2 [2×3+(8 -1)d]
192 = 4[6 +7d]
48 = 6+7d
42 = 7d
d = 6