How to solve the problem of arithmetic progressions of exercise 5.3 of class 10th math, How to solve this problem in easy problem In an AP (i) Given a = 5, d = 3, an = 50, find n and Sn.
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Given that, a = 5, d = 3, an = 50
As we know, from the formula of the nth term in an AP,
an = a +(n −1)d,
Therefore, putting the given values, we get,
⇒ 50 = 5+(n -1)×3
⇒ 3(n -1) = 45
⇒ n -1 = 15
⇒ n = 16
Now, sum of n terms,
Sn = n/2 (a +an)
Sn = 16/2 (5 + 50) = 440