What is the solution of introduction to trigonometry question of ncert class 10 .How i solve this question of exercise 8.1 question no.1(2) in a easy way please help me to solve this question fastly. In ∆ ABC, right-angled at B, AB = 24 cm, BC = 7 cm. Determine: (ii) sin C, cos C

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# In ∆ ABC, right-angled at B, AB = 24 cm, BC = 7 cm. Determine: (ii) sin C, cos C . Q.1(2)

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This answer was edited.In a given triangle ABC, right angled at B = ∠B = 90°

Given: AB = 24 cm and BC = 7 cm

According to the Pythagoras Theorem,

In a right- angled triangle, the squares of the hypotenuse side is equal to the sum of the squares of the other two sides.

By applying Pythagoras theorem, we get

AC

^{2}=AB^{2}+BC^{2}AC

^{2}= (24)^{2}+7^{2}AC

^{2}= (576+49)AC

^{2}= 625cm^{2}AC = √625 = 25

Therefore, AC = 25 cm

To find Sin (C), Cos (C)

Sin (C) = AB/AC = 24/25

Cos (C) = BC/AC = 7/25