One of the most important and exam oriented question as it was already asked in previous year paper of 2008 in which we have given that tanA=5/12, we asked to find the value of (sinA+cosA)secA
Kindly give me a detailed solution of this question
RS Aggarwal, Class 10, chapter 13C, question no 30
Given tanA=5/12
∴SinA=5/13
cosA=12/13
secA=13/12
(sinA+cosA)secA=(5/13 + 12/13)×13/12
=17/13×13/12
∴(sinA+cosA)secA
=17/12