One of the most important and exam oriented question as it was already asked in previous year paper of 2008 in which we have given that tanA=5/12, we asked to find the value of (sinA+cosA)secA

Kindly give me a detailed solution of this question

RS Aggarwal, Class 10, chapter 13C, question no 30

Given tanA=5/12

∴SinA=5/13

cosA=12/13

secA=13/12

(sinA+cosA)secA=(5/13 + 12/13)×13/12

=17/13×13/12

∴(sinA+cosA)secA

=17/12