0 SonuNewbie Asked: July 19, 20212021-07-19T18:13:57+05:30 2021-07-19T18:13:57+05:30In: NCERT Class 10th Maths If cot θ = 7/8, evaluate :(ii) cot2 θ .Q7(2) 0 Find this important question of introduction to trigonometry of class 10 ncert . Sir please help me to solve the exercise 8.1 question number 7(2), its very hard to solve . If cot θ = 7/8, evaluate :(ii) cot2 θ . best math ncert solutionexercise 8.1 ncertintroduction to trigonometry ncertncert class 10th solution Share Facebook 1 Answer Voted Oldest Recent bhagwansingh Guru 2021-07-29T13:43:47+05:30Added an answer on July 29, 2021 at 1:43 pm Let us assume a △ABC in which ∠B = 90° and ∠C = θ Given: cot θ = BC/AB = 7/8 Let BC = 7k and AB = 8k, where k is a positive real number According to Pythagoras theorem in △ABC we get. AC^{2 }= AB^{2}+BC^{2} AC^{2 }= (8k)^{2}+(7k)^{2} AC^{2 }= 64k^{2}+49k^{2} AC^{2 }= 113k^{2} AC = √113 k According to the sine and cos function ratios, it is written as sin θ = AB/AC = Opposite Side/Hypotenuse = 8k/√113 k = 8/√113 and cos θ = Adjacent Side/Hypotenuse = BC/AC = 7k/√113 k = 7/√113 Now apply the values of sin function and cos function: 0 Reply Share Share Share on Facebook Share on Twitter Share on LinkedIn Share on WhatsApp Leave an answerLeave an answerCancel reply Featured image Select file Browse Add a Video to describe the problem better. Video type Youtube Vimeo Dailymotion Facebook Choose from here the video type. Video ID Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs". Click on image to update the captcha. Save my name, email, and website in this browser for the next time I comment. Related Questions The distance (in km) of 40 engineers from their residence to their place of work were found as ... The blood groups of 30 students of Class VIII are recorded as follows: A, B, O, O, AB, ... Classify the data in Q.1 above as primary or secondary data. Q.2 Give five examples of data that you can collect from your day-to-day life. Q.1 A capsule of medicine is in the shape of a sphere of diameter 3.5mm. How much medicine (in ...

Let us assume a △ABC in which ∠B = 90° and ∠C = θ

Given:

cot θ = BC/AB = 7/8

Let BC = 7k and AB = 8k, where k is a positive real number

According to Pythagoras theorem in △ABC we get.

AC

^{2 }= AB^{2}+BC^{2}AC

^{2 }= (8k)^{2}+(7k)^{2}AC

^{2 }= 64k^{2}+49k^{2}AC

^{2 }= 113k^{2}AC = √113 k

According to the sine and cos function ratios, it is written as

sin θ = AB/AC = Opposite Side/Hypotenuse = 8k/√113 k = 8/√113 and

cos θ = Adjacent Side/Hypotenuse = BC/AC = 7k/√113 k = 7/√113

Now apply the values of sin function and cos function: