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Rajan@2021
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If (cotθ+tanθ) = m and (secθ-cosθ) = n, prove that (m²n)⅔ – (mn²)⅔ = 1

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This question is taken from trigonometry, topic – trigonometric identities in which we have given that (cotθ+tanθ) = m and also (secθ-cosθ) = n, we have been asked to  prove that (m²n)⅔ – (mn²)⅔ = 1

RS Aggarwal, Class 10, chapter 13B, question no 8

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