This is the Important question based on Arithmetic progression Chapter of R.S Aggarwal book for ICSE & CBSE Board.

In this Question three consecutive terms of an AP is given you have to find the value of term(a).

This is the Question Number 1 Of Exercise 11 D of RS Aggarwal Solution

Deepak BoraNewbie

# if 4/5,a,2 are three consecutive terms of an AP, find the value of a.

Share

Given 4/5,a,2 are

Difference of any two consecutive terms in A.P is equal

a-4/5=2-a

2a=2+4/5

2a=(10+4)/5

2a=14/5

a=14/2×5

a=7/5=1.4

Therefore,

Value of a=7/5=1.4