This is the Important question based on Arithmetic progression Chapter of R.S Aggarwal book for ICSE & CBSE Board.
In this Question three consecutive terms of an AP is given you have to find the value of term(a).
This is the Question Number 1 Of Exercise 11 D of RS Aggarwal Solution
Deepak BoraNewbie
if 4/5,a,2 are three consecutive terms of an AP, find the value of a.
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Given 4/5,a,2 are
Difference of any two consecutive terms in A.P is equal
a-4/5=2-a
2a=2+4/5
2a=(10+4)/5
2a=14/5
a=14/2×5
a=7/5=1.4
Therefore,
Value of a=7/5=1.4