The best way for solving the tough question of arithmetic progressions of exercise 5.2 of math of class 10th. How i solve in easy way If 17th term of an A.P. exceeds its 10th term by 7. Find the common difference.

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# If 17th term of an A.P. exceeds its 10th term by 7. Find the common difference. Q.10

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We know that, for an A.P series;

a=_{n}a+(n−1)da_{17}=a+(17−1)da_{17}=a+16dIn the same way,

a_{10}=a+9dAs it is given in the question,

a_{17}−a_{10}= 7Therefore,

(

a+16d)−(a+9d) = 77

d= 7d= 1Therefore, the common difference is 1.