The best way for solving the tough question of arithmetic progressions of exercise 5.2 of math of class 10th. How i solve in easy way If 17th term of an A.P. exceeds its 10th term by 7. Find the common difference.
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If 17th term of an A.P. exceeds its 10th term by 7. Find the common difference. Q.10
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We know that, for an A.P series;
an = a+(n−1)d
a17 = a+(17−1)d
a17 = a +16d
In the same way,
a10 = a+9d
As it is given in the question,
a17 − a10 = 7
Therefore,
(a +16d)−(a+9d) = 7
7d = 7
d = 1
Therefore, the common difference is 1.