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(i) (tan 25o/ cosec 65o)2 + (cot 25o/ sec 65o)2 + 2 tan 18o tan 45o tan 75o (ii) (cos2 25o + cos2 65o) + cosec θ sec (90o – θ) – cot θ tan (90o – θ)

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This is an important question taken from the Book- ML Aggarwal
Board- ICSE
Publication- Avichal
Chapter- Trigonometric Identities
Chapter number-18

(i) (tan 25o/ cosec 65o)2 + (cot 25o/ sec 65o)2 + 2 tan 18o tan 45o tan 75o (ii) (cos2 25o + cos2 65o) + cosec θ sec (90o – θ) – cot θ tan (90o – θ)

ML Aggarwal, ques no 9, ICSE board

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1 Answer

  1. Given,

    (i) (tan 25o/ cosec 65o)2 + (cot 25o/ sec 65o)2 + 2 tan 18o tan 45o tan 75o

    ML Aggarwal Solutions for Class 10 Chapter 18 - 6

    (ii) (cos2 25o + cos2 65o) + cosec θ sec (90o – θ) – cot θ tan (90o – θ)

    = cos2 25o + cos2 (90o – 25o) + cosec θ sec (90o – θ) – cot θ. cot θ

    = (cos2 25o + sin2 25o) + (cosec2 θ – cot2 θ)

    = 1 + 1 = 2

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