This is an important and very basic ques from the Book ML Aggarwal class 10th,, chapter – 7, ratio and proportion.
In this ques we have a:b, b:c and we have to find a:b:c
And in the second part we have 3a=4b=6c amd we have to find a:b:c
Question 10, ML Aggarwal
Solution:
(i) We know that
A: B = 1/4 × 5/1 = 5/4
B: C = 1/7 × 6/1 = 6/7
Here the LCM of B terms 4 and 6 is 12
Now making terms of B as 12
A/B = (5 × 3)/ (4 × 3) = 15/12 = 15: 12
B/C = (6 × 2)/ (7 × 2) = 12/14 = 12: 14
So A: B: C = 15: 12: 14
(ii) It is given that
3A = 4B
We can write it as
A/B = 4/3
A: B = 4: 3
Similarly 4B = 6C
We can write it as
B/C = 6/4 = 3/2
B: C = 3: 2
So we get
A: B: C = 4: 3: 2