0 AnilSinghBoraGuru Asked: July 15, 20212021-07-15T19:32:27+05:30 2021-07-15T19:32:27+05:30In: NCERT Class 10th Maths How many three digit numbers are divisible by 7? Q.13 0 In NCERT how to solve the question of arithmetic progressions of exercise 5.2 of class 10th of math. How to solve this problem How many three digit numbers are divisible by 7? arithmetic progressions ncertbest math solutionexercise 5.2 ncertncert class 10th solution Share Facebook 1 Answer Voted Oldest Recent bhagwansingh Guru 2021-07-15T20:15:06+05:30Added an answer on July 15, 2021 at 8:15 pm First three-digit number that is divisible by 7 are; First number = 105 Second number = 105+7 = 112 Third number = 112+7 =119 Therefore, 105, 112, 119, … All are three digit numbers are divisible by 7 and thus, all these are terms of an A.P. having first term as 105 and common difference as 7. As we know, the largest possible three-digit number is 999. When we divide 999 by 7, the remainder will be 5. Therefore, 999-5 = 994 is the maximum possible three-digit number that is divisible by 7. Now the series is as follows. 105, 112, 119, …, 994 Let 994 be the nth term of this A.P. first term, a = 105 common difference, d = 7 a_{n} = 994 n = ? As we know, a_{n} = a+(n−1)d 994 = 105+(n−1)7 889 = (n−1)7 (n−1) = 127 n = 128 Therefore, 128 three-digit numbers are divisible by 7. 0 Reply Share Share Share on Facebook Share on Twitter Share on LinkedIn Share on WhatsApp Leave an answerLeave an answerCancel reply Featured image Select file Browse Add a Video to describe the problem better. Video type Youtube Vimeo Dailymotion Facebook Choose from here the video type. Video ID Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs". Click on image to update the captcha. Save my name, email, and website in this browser for the next time I comment. Related Questions . Does Euclid’s fifth postulate imply the existence of parallel lines? Explain. Q.2 How would you rewrite Euclid’s fifth postulate so that it would be easier to understand? Q.1 A jar contains 24 marbles, some are green and others are blue. If a marble is drawn at ... A box contains 12 balls out of which x are black. If one ball is drawn at random ... A bag contains 5 red balls and some blue balls. If the probability of drawing a blue ball ...

First three-digit number that is divisible by 7 are;

First number = 105

Second number = 105+7 = 112

Third number = 112+7 =119

Therefore, 105, 112, 119, …

All are three digit numbers are divisible by 7 and thus, all these are terms of an A.P. having first term as 105 and common difference as 7.

As we know, the largest possible three-digit number is 999.

When we divide 999 by 7, the remainder will be 5.

Therefore, 999-5 = 994 is the maximum possible three-digit number that is divisible by 7.

Now the series is as follows.

105, 112, 119, …, 994

Let 994 be the nth term of this A.P.

first term, a = 105

common difference, d = 7

a

_{n}= 994n = ?

As we know,

a

_{n}= a+(n−1)d994 = 105+(n−1)7

889 = (n−1)7

(n−1) = 127

n = 128

Therefore, 128 three-digit numbers are divisible by 7.