• 0
Newbie

# From each corner of a square of side 4 cm a quadrant of a circle of radius 1 cm is cut and also a circle of diameter 2 cm is cut as shown in Fig. 12.23. Find the area of the remaining portion of the square. Q.5

• 0

In ncert class 10 chapter areas related to circle what is the best solution of the exercise 12.3 question number 5 ,Please help me to solve this question in a easiest and simplest way . Give me the best solution of this question .From each corner of a square of side 4 cm a quadrant of a circle of radius 1 cm is cut and also a circle of diameter 2 cm is cut as shown in Fig. 12.23. Find the area of the remaining portion of the square.

Share

1. Side of the square = 4 cm

Radius of the circle = 1 cm

Four quadrant of a circle are cut from corner and one circle of radius are cut from middle.

Area of square = (side)2= 42Â = 16 cm2

Area of the quadrant = (Ï€R2)/4 cm2Â = (22/7)Ã—(12)/4 = 11/14 cm2

âˆ´ Total area of the 4 quadrants = 4 Ã—(11/14) cm2Â = 22/7 cm2

Area of the circle = Ï€R2Â cm2Â = (22/7Ã—12) = 22/7 cm2

Area of the shaded region = Area of square â€“ (Area of the 4 quadrants + Area of the circle)

= 16 cm2-(22/7) cm2+(22/7) cm2

= 68/7 cm2

• 0