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Deepak Bora
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From a solid cylinder of height 14 cm and base diameter 7 cm, two equal conical holes each of radius 2.1 cm and height 4 cm are cut off. Find the volume of the remaining solid.

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This is the important question from the exam point of view last time this question was asked in 2011 cbse board exam. This question from RS Aggarwal book Exercises 17A page number 788, chapter volume and surface area of solid, question number 24

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  1. This answer was edited.

    Given data,
    Height of the solid cylinder = 14 cm

    Diameter of the solid cylinder = 7 cm

    Volume of cylinder= π× r² ×h

    = 22/7 × 3.5² × 14

    = 539 cm³

    Volume of conical holes=[1/3] π × r² × h

    =[1/3] × [22/7] × [2.1]² × 4

    =18.48 cm³

    There are two conical holes,

    ∴ 2×18.48

    =36.96 cm³

    Remaining volume = 539 – 36.96

    =502.04 cm³

    ∴ Remaining volume of solid is 502.04 cm³

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