An important question from linear equations in two variables as it was already asked in various examinations in which we have been asked to find two numbers such that the sum of thrice the first and the second is 142, and four times the first exceeds the second by 138.
RS Aggarwal, Class 10, chapter 3E, question no 6
Let us consider,
First number =x and
Second number =y
As per the statement,
3x+y=142...(1)
4x−y=138...(2)
Using elimination method
Add (1) and (2), we get
7x=280
x=40
From (1):3×40+y=142
120+y=142
y=142−120=22
Answer
First number 40
Second number =22