0 Deepak BoraNewbie Asked: July 24, 20202020-07-24T14:55:05+05:30 2020-07-24T14:55:05+05:30In: CBSE Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients. 0 NCERT / CBSE QUESTION NO 1 (ii) CHAPTER 2.2 quadratic polynomials Share Facebook 1 Answer Voted Oldest Recent Deepak Bora Newbie 2020-07-24T15:14:48+05:30Added an answer on July 24, 2020 at 3:14 pm 4s2–2s–2s+1 = 2s(2s–1)–1(2s-1) = (2s–1)(2s–1) Therefore, zeroes of polynomial equation 4s2–4s+1 are (1/2, 1/2) Sum of zeroes = (½)+(1/2) = 1 = -4/4 = -(Coefficient of s)/(Coefficient of s2) Product of zeros = (1/2)×(1/2) = 1/4 = (Constant term)/(Coefficient of s2 ) 0 Reply Share Share Share on Facebook Share on Twitter Share on LinkedIn Share on WhatsApp Leave an answerLeave an answerCancel reply Featured image Select file Browse Add a Video to describe the problem better. Video type Youtube Vimeo Dailymotion Facebook Choose from here the video type. Video ID Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs". Click on image to update the captcha. Save my name, email, and website in this browser for the next time I comment. Related Questions 30. A well of diameter 2 m is dug 14 m deep. The earth taken out of it ... 29. A 16 m deep well with diameter 3.5 m is dug up, and the earth from it ... 28. A path 2 m wide surrounds a circular pond of diameter 40 m. How many cubic meters ... 27. A spherical ball of radius 3 cm is melted and recast into three spherical balls. The radii ... 26. A hollow sphere of internal and external radii 2 cm and 4 cm, respectively, is melted into ...
4s2–2s–2s+1
= 2s(2s–1)–1(2s-1)
= (2s–1)(2s–1)
Therefore, zeroes of polynomial equation 4s2–4s+1 are (1/2, 1/2)
Sum of zeroes = (½)+(1/2) = 1 = -4/4 = -(Coefficient of s)/(Coefficient of s2)
Product of zeros = (1/2)×(1/2) = 1/4 = (Constant term)/(Coefficient of s2 )