0 Deepak BoraNewbie Asked: July 24, 20202020-07-24T14:55:05+05:30 2020-07-24T14:55:05+05:30In: CBSE Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients. 0 NCERT / CBSE QUESTION NO 1 (ii) CHAPTER 2.2 quadratic polynomials Share Facebook 1 Answer Voted Oldest Recent Deepak Bora Newbie 2020-07-24T15:14:48+05:30Added an answer on July 24, 2020 at 3:14 pm 4s2–2s–2s+1 = 2s(2s–1)–1(2s-1) = (2s–1)(2s–1) Therefore, zeroes of polynomial equation 4s2–4s+1 are (1/2, 1/2) Sum of zeroes = (½)+(1/2) = 1 = -4/4 = -(Coefficient of s)/(Coefficient of s2) Product of zeros = (1/2)×(1/2) = 1/4 = (Constant term)/(Coefficient of s2 ) 0 Reply Share Share Share on Facebook Share on Twitter Share on LinkedIn Share on WhatsApp Leave an answerLeave an answerCancel reply Featured image Select file Browse Add a Video to describe the problem better. Video type Youtube Vimeo Dailymotion Facebook Choose from here the video type. Video ID Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs". Click on image to update the captcha. Save my name, email, and website in this browser for the next time I comment. Related Questions +91-9953525677 Call Girls In Delhi Gokulpuri Low Price✔️ Call Girl In Radisson Hotel Sector 29 Gurugram 9871031762 Door Step Escorts Service Lucknow escort carrier ultimate sexy clean newly profile available 24/7 Call Girls In Inderpuri, Delhi ((9958139682)) Buy It At Affordable Prices. Call Girls In Ber Sarai, Delhi ((9958139682)) Buy It At Affordable Prices.
4s2–2s–2s+1
= 2s(2s–1)–1(2s-1)
= (2s–1)(2s–1)
Therefore, zeroes of polynomial equation 4s2–4s+1 are (1/2, 1/2)
Sum of zeroes = (½)+(1/2) = 1 = -4/4 = -(Coefficient of s)/(Coefficient of s2)
Product of zeros = (1/2)×(1/2) = 1/4 = (Constant term)/(Coefficient of s2 )