0 Deepak BoraNewbie Asked: July 24, 20202020-07-24T14:55:05+05:30 2020-07-24T14:55:05+05:30In: CBSE Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients. 0 NCERT / CBSE QUESTION NO 1 (ii) CHAPTER 2.2 quadratic polynomials Share Facebook 1 Answer Voted Oldest Recent Deepak Bora Newbie 2020-07-24T15:14:48+05:30Added an answer on July 24, 2020 at 3:14 pm 4s^{2}–2s–2s+1 = 2s(2s–1)–1(2s-1) = (2s–1)(2s–1) Therefore, zeroes of polynomial equation 4s^{2}–4s+1 are (1/2, 1/2) Sum of zeroes = (½)+(1/2) = 1 = -4/4 = -(Coefficient of s)/(Coefficient of s^{2}) Product of zeros = (1/2)×(1/2) = 1/4 = (Constant term)/(Coefficient of s^{2 }) 0 Reply Share Share Share on Facebook Share on Twitter Share on LinkedIn Share on WhatsApp Leave an answerLeave an answerCancel reply Featured image Select file Browse Add a Video to describe the problem better. Video type Youtube Vimeo Dailymotion Facebook Choose from here the video type. Video ID Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs". Click on image to update the captcha. Save my name, email, and website in this browser for the next time I comment. Related Questions Call Girls in Sharjah Ajman Call Girls Call Girls in Dubai Call Girls JBR დ 00971526940039 E2e Pakistani Call girls in JBR (UAE) (T1) 00971547881831 Call girls in Ajman (Contact Us) Cute Indian Call Girls in Ajman

4s

^{2}–2s–2s+1= 2s(2s–1)–1(2s-1)

= (2s–1)(2s–1)

Therefore, zeroes of polynomial equation 4s

^{2}–4s+1 are (1/2, 1/2)Sum of zeroes = (½)+(1/2) = 1 = -4/4 = -(Coefficient of s)/(Coefficient of s

^{2})Product of zeros = (1/2)×(1/2) = 1/4 = (Constant term)/(Coefficient of s

^{2 })