How i solve this ncert class 10th solution, of quadratic equation of exercise 4.4. I don’t know how to solve this question Find the values of k for each of the following quadratic equations, so that they have two equal roots.(ii) kx (x – 2) + 6 = 0

AnilSinghBoraGuru

# Find the values of k for each of the following quadratic equations, so that they have two equal roots.(ii) kx (x – 2) + 6 = 0 Q.2(2)

Share

kx(x– 2) + 6 = 0or

kx^{2}– 2kx+ 6 = 0Comparing the given equation with

ax^{2}+bx+c= 0, we geta=k,b= – 2kandc= 6We know, Discriminant =

b^{2}– 4ac= ( – 2

k)^{2}– 4 (k) (6)= 4

k– 24^{2}kFor equal roots, we know,

b^{2}– 4ac= 04

k^{2}– 24k= 04

k(k– 6) = 0Either 4

k= 0 ork= 6 = 0k= 0 ork= 6However, if

k= 0, then the equation will not have the terms ‘x^{2}‘ and ‘x‘.Therefore, if this equation has two equal roots,

kshould be 6 only.