1 AnilSinghBoraGuru Asked: July 16, 20212021-07-16T09:30:21+05:30 2021-07-16T09:30:21+05:30In: NCERT Class 10th Maths Find the sum of the odd numbers between 0 and 50. Q.14 1 The tricky question of class 10th math of arithmetic progressions ncert how i solve the problem of this question in easy way Find the sum of the odd numbers between 0 and 50. arithmetic progressions ncertbest math solutionexercise 5.3 ncertncert class 10th solution Share Facebook 1 Answer Voted Oldest Recent bhagwansingh Guru 2021-07-16T10:34:44+05:30Added an answer on July 16, 2021 at 10:34 am The odd numbers between 0 and 50 are 1, 3, 5, 7, 9 … 49. Therefore, we can see that these odd numbers are in the form of A.P. Hence, First term, a = 1 Common difference, d = 2 Last term, l = 49 By the formula of last term, we know, l = a+(n−1) d 49 = 1+(n−1)2 48 = 2(n − 1) n − 1 = 24 n = 25 = Number of terms By the formula of sum of nth term, we know, S_{n} = n/2(a +l) S_{25} = 25/2 (1+49) = 25(50)/2 =(25)(25) = 625 0 Reply Share Share Share on Facebook Share on Twitter Share on LinkedIn Share on WhatsApp Leave an answerLeave an answerCancel reply Featured image Select file Browse Add a Video to describe the problem better. Video type Youtube Vimeo Dailymotion Facebook Choose from here the video type. Video ID Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs". Click on image to update the captcha. Save my name, email, and website in this browser for the next time I comment. Related Questions A jar contains 24 marbles, some are green and others are blue. If a marble is drawn at ... A box contains 12 balls out of which x are black. If one ball is drawn at random ... A bag contains 5 red balls and some blue balls. If the probability of drawing a blue ball ... A die is numbered in such a way that its faces show the numbers 1, 2, 2, 3, ... Two customers Shyam and Ekta are visiting a particular shop in the same week (Tuesday to Saturday). Each ...

The odd numbers between 0 and 50 are 1, 3, 5, 7, 9 … 49.

Therefore, we can see that these odd numbers are in the form of A.P.

Hence,

First term, a = 1

Common difference, d = 2

Last term,

l= 49By the formula of last term, we know,

l=a+(n−1)d49 = 1+(

n−1)248 = 2(

n− 1)n− 1 = 24n= 25 = Number of termsBy the formula of sum of nth term, we know,

S=_{n}n/2(a+l)S= 25/2 (1+49)_{25}= 25(50)/2

=(25)(25)

= 625