The best way for solving the question of arithmetic progressions of exercise 5.3 of math, How i solve this question in easy way Find the sum of the following APs.(iii) 0.6, 1.7, 2.8 ,…….., to 100 terms
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Find the sum of the following APs.(iii) 0.6, 1.7, 2.8 ,…….., to 100 terms Q.1(3)
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Given, 0.6, 1.7, 2.8 ,…, to 100 terms
For this A.P.,
first term, a = 0.6
Common difference, d = a2 − a1 = 1.7 − 0.6 = 1.1
n = 100
We know that, the formula for sum of nth term in AP series is,
Sn = n/2[2a +(n-1)d]
S12 = 50/2 [1.2+(99)×1.1]
= 50[1.2+108.9]
= 50[110.1]
= 5505