Find the sum of the following AP. 0.6, 1.7, 2.8 ,…….., to 100 terms.

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The question is given from ncert Book of class 10th Chapter no. 5 Ex. 5.3 Q. 1 (iii). In the following question you have to find the sum of the A.P 0.6, 1.7, 2.8 ,…….., to 100 terms. Give the solution briefly.

Given, 0.6, 1.7, 2.8 ,…, to 100 terms

For this A.P.,

first term, a = 0.6

Common difference, d = a

_{2}− a_{1}= 1.7 − 0.6 = 1.1n = 100

We know that, the formula for sum of nth term in AP series is,

S

_{n}= n/2[2a +(n-1)d]S= 50/2 [1.2+(99)×1.1]_{12}= 50[1.2+108.9]

= 50[110.1]

= 5505