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Deepak Bora
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Find the sum of the following AP. 0.6, 1.7, 2.8 ,…….., to 100 terms.

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The question is given from ncert Book of class 10th Chapter no. 5 Ex. 5.3 Q. 1 (iii). In the following question you have to find the sum of the A.P 0.6, 1.7, 2.8 ,…….., to 100 terms. Give the solution briefly.

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  1. Given, 0.6, 1.7, 2.8 ,…, to 100 terms

    For this A.P.,

    first term, a = 0.6

    Common difference, d = a2 − a1 = 1.7 − 0.6 = 1.1

    n = 100

    We know that, the formula for sum of nth term in AP series is,

    Sn = n/2[2a +(n-1)d]

    S12 = 50/2 [1.2+(99)×1.1]

    = 50[1.2+108.9]

    = 50[110.1]

    = 5505

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