ICSE & CBSE Board Question Based on Arithmetic Progression of RS Aggarwal

In this Question you have to find the sum of first *n* even natural numbers.

This is the Question Number 14 Of Exercise 11D of RS Aggarwal Solution.

# Find the sum of first n even natural numbers.

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Even natural numbers = 2,4,6,8,….

d=4-2=2

Sn=n/2[2a+(n-1)d]

Sn=n/2[2×2+(n-1)2]

Sn=n/2[4+2n-2]

Sn=n/2[2n+2]

Sn=2n^2+2n/2

Sn=2(n^2+n)/2

Sn=n^2+n

Sum of first n even natural numbers = n square +n