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AnilSinghBora
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Find the sum of first 15 multiples of 8. Q.13

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Sir please help me for solving the problem  of class 10th math of arithmetic progressions of exercise 5.3 of math, how i solve this problem in easy way Find the sum of first 15 multiples of 8.

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2 Answers

  1. The multiples of 8 are 8, 16, 24, 32…

    The series is in the form of AP, having first term as 8 and common difference as 8.

    Therefore, a = 8

    d = 8

    S15 = ?

    By the formula of sum of nth term, we know,

    Sn = n/2 [2a+(n-1)d]

    S15 = 15/2 [2(8) + (15-1)8]

    = 15/2[6 +(14)(8)]

    = 15/2[16 +112]

    = 15(128)/2

    = 15 × 64

    = 960

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  2. This is the video solution for question 13 exercise 5.3 chapter 5 Arithmetic Progression class 10 NCERT. Hope you will like it!!!

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