1 AnilSinghBoraGuru Asked: July 16, 20212021-07-16T09:28:18+05:30 2021-07-16T09:28:18+05:30In: NCERT Class 10th Maths Find the sum of first 15 multiples of 8. Q.13 1 Sir please help me for solving the problem of class 10th math of arithmetic progressions of exercise 5.3 of math, how i solve this problem in easy way Find the sum of first 15 multiples of 8. arithmetic progressions ncertbest math solutionexercise 5.3 ncertncert class 10th solution Share Facebook 2 Answers Voted Oldest Recent bhagwansingh Guru 2021-07-16T10:35:15+05:30Added an answer on July 16, 2021 at 10:35 am The multiples of 8 are 8, 16, 24, 32… The series is in the form of AP, having first term as 8 and common difference as 8. Therefore, a = 8 d = 8 S_{15} = ? By the formula of sum of nth term, we know, S_{n} = n/2 [2a+(n-1)d] S_{15} = 15/2 [2(8) + (15-1)8] = 15/2[6 +(14)(8)] = 15/2[16 +112] = 15(128)/2 = 15 × 64 = 960 2 Reply Share Share Share on Facebook Share on Twitter Share on LinkedIn Share on WhatsApp Deepak Bora Newbie 2022-03-09T13:43:01+05:30Added an answer on March 9, 2022 at 1:43 pm This is the video solution for question 13 exercise 5.3 chapter 5 Arithmetic Progression class 10 NCERT. Hope you will like it!!! 0 Reply Share Share Share on Facebook Share on Twitter Share on LinkedIn Share on WhatsApp Leave an answerLeave an answerCancel reply Featured image Select file Browse Add a Video to describe the problem better. Video type Youtube Vimeo Dailymotion Facebook Choose from here the video type. Video ID Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs". Click on image to update the captcha. Save my name, email, and website in this browser for the next time I comment. Related Questions A jar contains 24 marbles, some are green and others are blue. If a marble is drawn at ... A box contains 12 balls out of which x are black. If one ball is drawn at random ... A bag contains 5 red balls and some blue balls. If the probability of drawing a blue ball ... A die is numbered in such a way that its faces show the numbers 1, 2, 2, 3, ... Two customers Shyam and Ekta are visiting a particular shop in the same week (Tuesday to Saturday). Each ...

The multiples of 8 are 8, 16, 24, 32…

The series is in the form of AP, having first term as 8 and common difference as 8.

Therefore,

a= 8d= 8S_{15}= ?By the formula of sum of nth term, we know,

S=_{n}n/2 [2a+(n-1)d]S= 15/2 [2(8) + (15-1)8]_{15}= 15/2[6 +(14)(8)]

= 15/2[16 +112]

= 15(128)/2

= 15 × 64

= 960

This is the video solution for question 13 exercise 5.3 chapter 5 Arithmetic Progression class 10 NCERT. Hope you will like it!!!