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Find the sub-duplicate ratio of (i) 9: 16 (ii) ¼: 1/9 (iii) 9a2: 49b2

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This is an important ques from the Book ML Aggarwal class 10th,, chapter – 7, ratio and proportion.

In this question we have been given a ratio in the form of a:b  and we have to find the sub-duplicate ratio of them.

ML Aggarwal, question 5

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  1. Solution:

    (i) 9: 16

    We know that

    Sub-duplicate ratio of 9: 16 = √9: √16 = 3: 4

    (ii) ¼: 1/9

    We know that

    Sub-duplicate ratio of ¼: 1/9 = √1/4: √1/9

    So we get

    = ½: 1/3

    = 3: 2

    (iii) 9a2: 49b2

    We know that

    Sub-duplicate ratio of 9a2: 49b2 = √9a2: √49b2 = 3a: 7b

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