In this question, we have to find the smallest number which when increased by 20 is exactly divisible by 90 and 144. This is an important question from Chapter 1 real number ncert book CBSE board.
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Find the smallest number which when increased by 20 is exactly divisible by 90 and 144.
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First we will find the LCM of given numbers
i.e
18×5×8=720
Required smallest number
720-20=700
Hence answer is 700