This is the basic and exam oriented question from real numbers in which we have given two numbers 468 and 520 and we have to find the smallest number which when increased by 17 is exactly divisible by both the above numbers.
Kindly give me a detailed solution of this question
RS Aggarwal, Class 10, chapter 1B, question no 12
The given numbers are 520 and 468.
The smallest number which when increased by 17 is exactly divisible by both 520 and 468 is obtained by subtracting 17 from the LCM of 520 and 468.
520=2×2×2×5×13
468=2×2×3×3×13
LCM of 520 and 468 = 2×2×2×3×3×5×13
=4680
Smallest number which when increased by 17 is exactly divisible by both 520 and 468=4680−17
=4663