Find the ratio in which the line x – 3y = 0 divides the line segment joining the points (– 2, – 5) and (6, 3). Find the coordinates of the point of intersection.

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Deepak BoraNewbie

Asked: July 26, 20202020-07-26T21:24:51+05:30 2020-07-26T21:24:51+05:30In: CBSE

CBSE 10th Class past year question paper

Year 2019

SET 1, Code Number- 30/2/1

Question number – 16

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Deepak Bora · Answer 1 · 2020-07-29T07:36:57+05:30

Deepak Bora Newbie

Let the line x – 3y = 0 intersect the segment

joining A(–2, –5) and B(6, 3) in the ratio k : 1

∴ Coordinates of P are [ {(6k – 2) / ( k + 1)}, { ( 3 k – 5 ) / ( k + 1)} ]

P lies on x – 3y = 0

{(6k – 2) / ( k + 1)} = 3 { ( 3 k – 5 ) / ( k + 1)}

k = 13/3

∴ Ratio is 13 : 3

Coordinates of P are [ ( 9/2), (3/2) ]